Optimal. Leaf size=168 \[ \frac{b \left (C \left (6 a^2+b^2\right )+2 A b^2\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{1}{2} a x \left (a^2 (A+2 C)+6 A b^2\right )-\frac{3 a b^2 (3 A-2 C) \tan (c+d x)}{2 d}+\frac{3 A b \sin (c+d x) (a+b \sec (c+d x))^2}{2 d}+\frac{A \sin (c+d x) \cos (c+d x) (a+b \sec (c+d x))^3}{2 d}-\frac{b^3 (4 A-C) \tan (c+d x) \sec (c+d x)}{2 d} \]
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Rubi [A] time = 0.393104, antiderivative size = 168, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {4095, 4094, 4048, 3770, 3767, 8} \[ \frac{b \left (C \left (6 a^2+b^2\right )+2 A b^2\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{1}{2} a x \left (a^2 (A+2 C)+6 A b^2\right )-\frac{3 a b^2 (3 A-2 C) \tan (c+d x)}{2 d}+\frac{3 A b \sin (c+d x) (a+b \sec (c+d x))^2}{2 d}+\frac{A \sin (c+d x) \cos (c+d x) (a+b \sec (c+d x))^3}{2 d}-\frac{b^3 (4 A-C) \tan (c+d x) \sec (c+d x)}{2 d} \]
Antiderivative was successfully verified.
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Rule 4095
Rule 4094
Rule 4048
Rule 3770
Rule 3767
Rule 8
Rubi steps
\begin{align*} \int \cos ^2(c+d x) (a+b \sec (c+d x))^3 \left (A+C \sec ^2(c+d x)\right ) \, dx &=\frac{A \cos (c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{2 d}+\frac{1}{2} \int \cos (c+d x) (a+b \sec (c+d x))^2 \left (3 A b+a (A+2 C) \sec (c+d x)-2 b (A-C) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{3 A b (a+b \sec (c+d x))^2 \sin (c+d x)}{2 d}+\frac{A \cos (c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{2 d}+\frac{1}{2} \int (a+b \sec (c+d x)) \left (6 A b^2+a^2 (A+2 C)-a b (A-4 C) \sec (c+d x)-2 b^2 (4 A-C) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{3 A b (a+b \sec (c+d x))^2 \sin (c+d x)}{2 d}+\frac{A \cos (c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{2 d}-\frac{b^3 (4 A-C) \sec (c+d x) \tan (c+d x)}{2 d}+\frac{1}{4} \int \left (2 a \left (6 A b^2+a^2 (A+2 C)\right )+2 b \left (2 A b^2+\left (6 a^2+b^2\right ) C\right ) \sec (c+d x)-6 a b^2 (3 A-2 C) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{1}{2} a \left (6 A b^2+a^2 (A+2 C)\right ) x+\frac{3 A b (a+b \sec (c+d x))^2 \sin (c+d x)}{2 d}+\frac{A \cos (c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{2 d}-\frac{b^3 (4 A-C) \sec (c+d x) \tan (c+d x)}{2 d}-\frac{1}{2} \left (3 a b^2 (3 A-2 C)\right ) \int \sec ^2(c+d x) \, dx+\frac{1}{2} \left (b \left (2 A b^2+\left (6 a^2+b^2\right ) C\right )\right ) \int \sec (c+d x) \, dx\\ &=\frac{1}{2} a \left (6 A b^2+a^2 (A+2 C)\right ) x+\frac{b \left (2 A b^2+\left (6 a^2+b^2\right ) C\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{3 A b (a+b \sec (c+d x))^2 \sin (c+d x)}{2 d}+\frac{A \cos (c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{2 d}-\frac{b^3 (4 A-C) \sec (c+d x) \tan (c+d x)}{2 d}+\frac{\left (3 a b^2 (3 A-2 C)\right ) \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{2 d}\\ &=\frac{1}{2} a \left (6 A b^2+a^2 (A+2 C)\right ) x+\frac{b \left (2 A b^2+\left (6 a^2+b^2\right ) C\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{3 A b (a+b \sec (c+d x))^2 \sin (c+d x)}{2 d}+\frac{A \cos (c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{2 d}-\frac{3 a b^2 (3 A-2 C) \tan (c+d x)}{2 d}-\frac{b^3 (4 A-C) \sec (c+d x) \tan (c+d x)}{2 d}\\ \end{align*}
Mathematica [A] time = 1.91745, size = 287, normalized size = 1.71 \[ \frac{2 a (c+d x) \left (a^2 (A+2 C)+6 A b^2\right )-2 b \left (C \left (6 a^2+b^2\right )+2 A b^2\right ) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+2 b \left (C \left (6 a^2+b^2\right )+2 A b^2\right ) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )+12 a^2 A b \sin (c+d x)+a^3 A \sin (2 (c+d x))+\frac{12 a b^2 C \sin \left (\frac{1}{2} (c+d x)\right )}{\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )}+\frac{12 a b^2 C \sin \left (\frac{1}{2} (c+d x)\right )}{\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )}+\frac{b^3 C}{\left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )^2}-\frac{b^3 C}{\left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^2}}{4 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.07, size = 196, normalized size = 1.2 \begin{align*}{\frac{A{a}^{3}\sin \left ( dx+c \right ) \cos \left ( dx+c \right ) }{2\,d}}+{\frac{{a}^{3}Ax}{2}}+{\frac{A{a}^{3}c}{2\,d}}+{a}^{3}Cx+{\frac{C{a}^{3}c}{d}}+3\,{\frac{A{a}^{2}b\sin \left ( dx+c \right ) }{d}}+3\,{\frac{{a}^{2}bC\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+3\,Aa{b}^{2}x+3\,{\frac{Aa{b}^{2}c}{d}}+3\,{\frac{Ca{b}^{2}\tan \left ( dx+c \right ) }{d}}+{\frac{A{b}^{3}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+{\frac{C{b}^{3}\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{2\,d}}+{\frac{C{b}^{3}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.01732, size = 242, normalized size = 1.44 \begin{align*} \frac{{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} A a^{3} + 4 \,{\left (d x + c\right )} C a^{3} + 12 \,{\left (d x + c\right )} A a b^{2} - C b^{3}{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 6 \, C a^{2} b{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 2 \, A b^{3}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 12 \, A a^{2} b \sin \left (d x + c\right ) + 12 \, C a b^{2} \tan \left (d x + c\right )}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.558954, size = 419, normalized size = 2.49 \begin{align*} \frac{2 \,{\left ({\left (A + 2 \, C\right )} a^{3} + 6 \, A a b^{2}\right )} d x \cos \left (d x + c\right )^{2} +{\left (6 \, C a^{2} b +{\left (2 \, A + C\right )} b^{3}\right )} \cos \left (d x + c\right )^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) -{\left (6 \, C a^{2} b +{\left (2 \, A + C\right )} b^{3}\right )} \cos \left (d x + c\right )^{2} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (A a^{3} \cos \left (d x + c\right )^{3} + 6 \, A a^{2} b \cos \left (d x + c\right )^{2} + 6 \, C a b^{2} \cos \left (d x + c\right ) + C b^{3}\right )} \sin \left (d x + c\right )}{4 \, d \cos \left (d x + c\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.24466, size = 522, normalized size = 3.11 \begin{align*} \frac{{\left (A a^{3} + 2 \, C a^{3} + 6 \, A a b^{2}\right )}{\left (d x + c\right )} +{\left (6 \, C a^{2} b + 2 \, A b^{3} + C b^{3}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) -{\left (6 \, C a^{2} b + 2 \, A b^{3} + C b^{3}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) - \frac{2 \,{\left (A a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 6 \, A a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 6 \, C a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - C b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 3 \, A a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 6 \, A a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 6 \, C a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 3 \, C b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 3 \, A a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 6 \, A a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 6 \, C a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 3 \, C b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - A a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 6 \, A a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 6 \, C a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - C b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 1\right )}^{2}}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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